Question

The velocity-time graph of a particle in straight line motion is shown in figure. The particle starts its motion from origin.

The displacement of the particle from the origin after $8s$ is

• A. $18m$
• B. $16m$
• C. $8m$
• D. $6m$

Answer 1

The correct option is D $6m$

Displacement of particle = Area under the $v-t$ graph $=[(\frac{1}{2}\times 1\times 4)+(2\times 4)+(\frac{1}{2}\times 1\times 4))]-[(\frac{1}{2}\times 1\times 2)+(2\times 2)+(\frac{1}{2}\times 1\times 2)]$
$=12-6=6m$