1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The velocity-time graph of a particle in straight-line motion is shown in the figure. The particle starts its motion from the origin. The distance travelled by the particle in 8 s is

A
18 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
16 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 18 m We know that, sum of magnitudes of areas formed under v−t graph represents the distance travelled by the particle ∴ total distance travelled in 8 s = Sum of areas of both the trapeziums formed in the graph =[(12×1×4)+(2×4)+(12×1×4))]+[(12×1×2)+(2×2)+(12×1×2)] =12+6=18 m

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Acceleration
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program