Question

The velocity-time graph of a particle in straight-line motion is shown in the figure. The particle starts its motion from the origin.

The displacement of the particle in $8s$ is

• A. $12\text{m}$
• B. $6\text{m}$
• C. $18\text{m}$
• D. $24\text{m}$

Answer 1

The correct option is B $6\text{m}$


We know that, areas formed under $v-t$ graph represents the displacement of the particle
$\therefore$ total displacement in $8s$ is given by areas of both the trapeziums formed in the graph
$D=\frac{1}{2}\times (4+2)\times 4-\frac{1}{2}\times (4+2)\times 2$
$=12-6=6\text{m}$