Question

The velocity-time graph of a particle in straight-line motion is shown in the figure. The particle starts its motion from the origin.

The distance travelled by the particle in $8s$ is

• A. $18m$
• B. $16m$
• C. $8m$
• D. $6m$

Answer 1

The correct option is A $18m$


We know that, sum of magnitudes of areas formed under $v-t$ graph represents the distance travelled by the particle
$\therefore$ total distance travelled in $8s$
= Sum of areas of both the trapeziums formed in the graph
$=[(\frac{1}{2}\times 1\times 4)+(2\times 4)+(\frac{1}{2}\times 1\times 4))]+[(\frac{1}{2}\times 1\times 2)+(2\times 2)+(\frac{1}{2}\times 1\times 2)]$
$=12+6=18m$