The velocity-time graph of a particle of mass 50 g moving in a fixed direction. The force on the particle is

25 N

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25 \times 10^{- 1} N

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25 \times 10^{2} N

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25 \times 10^{- 3} N

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Solution

The correct option is D $25 \times 10^{- 3} N$
$a = S l o p e o f V e l o c i t y - t i m e g r a p h = \frac{2}{4} = \frac{1}{2} m / s^{2} F = m a = 50 \times 10^{- 3} \times \frac{1}{2} = 25 \times 10^{- 3} N e w t o n$

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The velocity-time graph of a particle of mass 50 g moving in a fixed direction. The force on the particle is

The correct option is D 25×10−3 Na=Slope of Velocity−time graph=24=12m/s2F=ma=50×10−3×12=25×10−3 Newton

The correct option is D $25 \times 10^{- 3} N$
$a = S l o p e o f V e l o c i t y - t i m e g r a p h = \frac{2}{4} = \frac{1}{2} m / s^{2} F = m a = 50 \times 10^{- 3} \times \frac{1}{2} = 25 \times 10^{- 3} N e w t o n$