The velocity-time graph of a stone thrown vertically upward with an initial velocity of $30 m / s$ is shown in the figure. The velocity in the upward direction is taken as positive and that in the downward direction as negative. What is the maximum height to which the stone rises? ( $g = 9.5$ )

30 m

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45 m

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60 m

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90 m

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Solution

The correct option is B 45 m
At minimum height $v = 0$
$∴$ max height = area of $△$ OAB
$H = \frac{1}{2} \times 3 \times 30 = 45 m$

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The velocity-time graph of a stone thrown vertically upward with an initial velocity of 30 m/s is shown in the figure. The velocity in the upward direction is taken as positive and that in the downward direction as negative. What is the maximum height to which the stone rises? (g=9.5)

The correct option is B 45 mAt minimum height v=0∴ max height = area of △ OABH=12×3×30=45 m

The velocity-time graph of a stone thrown vertically upward with an initial velocity of $30 m / s$ is shown in the figure. The velocity in the upward direction is taken as positive and that in the downward direction as negative. What is the maximum height to which the stone rises? ( $g = 9.5$ )

The correct option is B 45 m
At minimum height $v = 0$
$∴$ max height = area of $△$ OAB
$H = \frac{1}{2} \times 3 \times 30 = 45 m$