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Question

The velocity-time graph of linear motion is shown in the figure. The displacement from the origin after 8sec is


1517916_010e4802478440aa8d8ab98c4d18de88.PNG

A
5m
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B
16m
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C
8m
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D
6m
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Solution

The correct option is D 6m
The displacement in the velocity-time graph is equal to the area under the graph.
From the graph,
The displacement from time t=0sec to t=4sec is
S=12×4×4+2=12m
The displacement from time t=4sec to t=8sec is,
S′′=12×2×4+2=6m
Total displacement , S=S+S′′
S=12m6m=6m
The correct option is D.

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