Question

The velocity-time graph of linear motion is shown in the figure. The displacement from the origin after $8sec$ is

• A. $5m$
• B. $16m$
• C. $8m$
• D. $6m$

Answer 1

The correct option is D $6m$

The displacement in the velocity-time graph is equal to the area under the graph.

From the graph,

The displacement from time $t=0sec$ to $t=4sec$ is

$S^{\prime }=\frac{1}{2}\times 4\times 4+2=12m$

The displacement from time $t=4sec$ to $t=8sec$ is,

$S^{\prime \prime }=\frac{1}{2}\times -2\times 4+2=-6m$

Total displacement , $S=S^{\prime }+S^{\prime \prime }$

$S=12m-6m=6m$

The correct option is D.