The correct option is D 2⋅5 m/s
Avergae velocity=Total displacementtotal time
Area under the curve above x− axis ,
distance (D1)=12×20×5=50m
Area under the curve below x− axis,
distance (D2)=12×20×5=50m
Then, total Distance =100 m
Since, total time =40 sec
Then, average speed is given by,
Avergae velocity=Total displacementtotal time
vavg=100m40sec
vavg=2⋅5 m/s
Final Answer:b