Question

The velocity-time (v-t) graph for a particle moving on a straight line is shown here. Which of the following statements is correct?

• A. The particle has a variable acceleration
• B. The particle has never turned around
• C. The particle has zero displacement
• D. the average speed in the interval 0 to 5 s is the same as the average speed in the interval 5 to 10 s.

Answer 1

Answer: (D)

the average speed in the interval 0 to 5 s is the same as the average speed in the interval 5 to 10 s.

Here,

As the slope of $v-t$ graph is constant, acceleration is constant,

As velocity becomes positive to negative , it has turned around,

As the area under curve is overall negative, it has some displacement other than zero.

And it is clear from the graph that,

displacement in $0-5$ Sec is same as $5-10$ sec

And average velocity$=\frac{\text{total displacement}}{\text{total time}}$

Option $\text{D}$ is the correct answer