You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Relating Circular Motion to SHM

The velocity ...

Question

The velocity v of a particle at time t is given by v=at+ b/t+ c where a,b,c are constants . What will be the dimensions of a,b and c

Open in App

Solution

we follow the rule : when we add or subtract some terms, all these terms should be of the same dimensions to which they are equated.
so, [at] = [v]
[a] [T] = [LT^-1]
[a] = [LT^-2]
and, [b/t] = [v]
[b] [T^-1] = [LT^-1]
[b] = [L]
also, [c] = [v]
[c] = [LT^-1]

Suggest Corrections

195

Similar questions

The velocity $v$ of a particle at time $t$ is given by $v = a t + \frac{b}{t + c}$ where $a, b$ and $c$ are constants. The dimensions of $a, b$ and $c$ are respectively :

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

, where

a, b

and

c

are constant. The dimensions of

a, b

and

c

are respectively.

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

, where

a, b a n d c

are constants.The dimensions of

a, b a n d c

are respectively:

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

, where

a, b

and

c

are constants. The dimensions of

a, b

and

c

are respectively

Q. The velocity

v

of a particle at time

t

is given by

v = a t + \frac{b}{t + c}

The dimensions of

a, b, c

are respectively

Join BYJU'S Learning Program

The velocity v of a particle at time t is given by v=at+ b/t+ c where a,b,c are constants . What will be the dimensions of a,b and c

we follow the rule : when we add or subtract some terms, all these terms should be of the same dimensions to which they are equated.so, [at] = [v][a] [T] = [LT-1][a] = [LT-2]and, [b/t] = [v][b] [T-1] = [LT-1][b] = [L]also, [c] = [v][c] = [LT-1]

we follow the rule : when we add or subtract some terms, all these terms should be of the same dimensions to which they are equated.
so, [at] = [v]
[a] [T] = [LT^-1]
[a] = [LT^-2]
and, [b/t] = [v]
[b] [T^-1] = [LT^-1]
[b] = [L]
also, [c] = [v]
[c] = [LT^-1]