Question

The velocity vs time graph is given above. Find out the area under graph from 2s to 6s (in $m^2$) :

• A. 8
• B. 16
• C. 24
• D. 32
• E. 36

Answer 1

The correct option is C 24

From figure, $AB=4$ m/s $CD=8$m/s $AC=4$ s

Thus area under the graph from 2 s to 6 s , Area$=\frac{1}{2}\times [AB+CD]\times AC=\frac{1}{2}\times [4+8]\times 4=24$ $m^2$