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Standard IX

Physics

Vernier Caliper

The vernier c...

Question

The vernier constant of a vernier callipers is 0.1 mm. There are 10 divisions on Vernier scale. These 10 divisions coincides with N-divisions of main scale. Then N should be :

11

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9

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19

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10

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Solution

The correct option is B $9$
$vernier constant = 0.1 m m$
$vernier constant = least count$
$\begin{matrix} \Rightarrow L C = 1 M S D - 1 V S D Let 10 V S D = N M S D \Rightarrow 1 V S D = \frac{N}{10} M S D \end{matrix}$
$\Rightarrow L C = 1 M S D - \frac{N}{10} M S D = \frac{10 - N}{10} M S D$
$In Standard vernier Calipers 1MSD = 1 m m$
$\begin{matrix} L C & = \frac{10 - N}{10} m m = 0.1 m m \Rightarrow 10 - N = 1 \Rightarrow N = 9 \end{matrix}$

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The vernier constant of a vernier callipers is 0.1 mm. There are 10 divisions on Vernier scale. These 10 divisions coincides with N-divisions of main scale. Then N should be :

The correct option is B 9 vernier constant =0.1 mm vernier constant = least count ⇒LC=1MSD−1VSD Let 10VSD=NMSD⇒1VSD=N10MSD ⇒LC=1MSD−N10MSD=10−N10MSD In Standard vernier Calipers 1MSD =1 mm LC=10−N10mm=0.1mm⇒10−N=1⇒N=9