Question

The vernier constant (V.C) of vernier calipers is $0.01cm$. If $10$ divisions of the vernier scale is equivalent to $9$ divisions of the main scale then the value of one of the smallest division of the main scale is:

• A. $1cm$
• B. $1mm$
• C. $0.1mm$
• D. $0.01cm$

Answer 1

Answer: (B)

$1mm$

$V.C=\frac{Smallestdivisononthemainscale\left(S\right)}{Totalnumberofdivisonontheverneirscale}$
or $0.01=\frac{S}{10}\Rightarrow S=0.01\times 10=0.1cm=1mm$