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Question

The vertex and focus of a parabola are (1,2) and (1,-1). Then the equation of the tangent at the vertex is


A

x+2y-6=0

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B

x+2y-4=0

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C

x+2y-9=0

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D

x+2y-7=0

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Solution

The correct option is B

x+2y-4=0


A=(2,1),S=(1,1)

Slope of AS=2
perpendicular Slope=12

eqn of tangent at vertex y-1=12(x2)\
2y2=x+2
x+2y4=0


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