The vertex and focus of a parabola are (1,2) and (1,-1). Then the equation of the tangent at the vertex is

x+2y-6=0

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x+2y-4=0

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x+2y-9=0

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x+2y-7=0

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Solution

The correct option is B
x+2y-4=0

$A = (2, 1), S = (1, - 1)$

Slope of AS=2
perpendicular Slope= $\frac{- 1}{2}$

eqn of tangent at vertex y-1= $\frac{- 1}{2} (x - 2)$ \
$2 y - 2 = - x + 2$
$x + 2 y - 4 = 0$

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