The vertex of the parabola represented by the quadratic equation $y = x^{2} + 2 x + 6$ is

(1,-5)

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(-1,5)

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(1,-6)

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(-1,6)

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Solution

The correct option is B (-1,5)
Given equation $y = x^{2} + 2 x + 6$ can be written as:
$y = x^{2} + 2 x + 1 + 5 y - 5 = x^{2} + 2 x + 1 y - 5 = (x + 1)^{2}$
The vertex of a quadratic equation of the form $y - b = (x - a)^{2}$ is (a, b).

Comparing both the equations, a = -1, b = 5.

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The vertex of the parabola represented by the quadratic equation y=x2+2x+6 is

The correct option is B (-1,5)Given equation y=x2+2x+6 can be written as: y=x2+2x+1+5y−5=x2+2x+1y−5=(x+1)2 The vertex of a quadratic equation of the form y − b = (x −a)2 is (a, b). Comparing both the equations, a = -1, b = 5.

The vertex of the parabola represented by the quadratic equation $y = x^{2} + 2 x + 6$ is

The correct option is B (-1,5)
Given equation $y = x^{2} + 2 x + 6$ can be written as:
$y = x^{2} + 2 x + 1 + 5 y - 5 = x^{2} + 2 x + 1 y - 5 = (x + 1)^{2}$
The vertex of a quadratic equation of the form $y - b = (x - a)^{2}$ is (a, b).

Comparing both the equations, a = -1, b = 5.