The vertex of the parabola $x^{2} = 2 (2 x + y)$ is

(- 2, 1)

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(- 1, 1)

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(- 2, 0)

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(2, - 2)

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Solution

The correct option is B $(2, - 2)$
Given $x^{2} = 2 (2 x + y)$
$\Rightarrow x^{2} - 4 x + 4 = 2 y + 4 = 2 (y + 2)$
$\Rightarrow (x - 2)^{2} = 2 (y + 2)$
So vertex of the parabola is $(2, - 2)$

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The vertex of the parabola x2=2(2x+y) is

The correct option is B (2,−2)Given x2=2(2x+y)⇒x2−4x+4=2y+4=2(y+2)⇒(x−2)2=2(y+2)So vertex of the parabola is (2,−2)

The vertex of the parabola $x^{2} = 2 (2 x + y)$ is

The correct option is B $(2, - 2)$
Given $x^{2} = 2 (2 x + y)$
$\Rightarrow x^{2} - 4 x + 4 = 2 y + 4 = 2 (y + 2)$
$\Rightarrow (x - 2)^{2} = 2 (y + 2)$
So vertex of the parabola is $(2, - 2)$