The vertex of the parabola $x^{2} + 8 x + 12 y + 4 = 0$ is

(0, 0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(- 4, 1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(1, - 4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(4, - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(- 4, 1)$
The equation of parabola is
$x^{2} + 8 x + 12 y + 4 = 0 \Rightarrow (x + 4)^{2} - 16 + 12 y + 4 = 0 \Rightarrow (x + 4)^{2} - 12 + 12 y = 0 \Rightarrow (x + 4)^{2} = - 12 y + 12 \Rightarrow (x + 4)^{2} = - 12 (y - 1)$
$∴$ Vertex is $(- 4, 1)$

Suggest Corrections

Similar questions

The vertex of the parabola $x^{2} + 8 x + 12 y + 4 = 0$ is

x^{2} + 8 x + 12 y + 4 = 0

x^{2} + 2 y = 8 x - 7

x^{2} + 2 y = 8 x - 7

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program