The vertex of the parabola $x^{2} + 8 x + 12 y + 4 = 0$ is

(- 4, 1)

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(4, - 1)

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(- 4, - 1)

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(4, 1)

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Solution

The correct option is A $(- 4, 1)$
The equation is re-written as,
$(x + 4)^{2} + 12 (y - 1) = 0$
$(- 4, 1)$ is the vertex.

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The vertex of the parabola x2+8x+12y+4=0 is

The correct option is A (−4,1)The equation is re-written as,(x+4)2+12(y−1)=0(−4,1) is the vertex.

The vertex of the parabola $x^{2} + 8 x + 12 y + 4 = 0$ is

The correct option is A $(- 4, 1)$
The equation is re-written as,
$(x + 4)^{2} + 12 (y - 1) = 0$
$(- 4, 1)$ is the vertex.