Question

The vertex of the parabola $x^2+8x+12y+4=0$ is

• A. $(0,0)$
• B. $(-4,1)$
• C. $(1,-4)$
• D. $(4,-1)$

Answer 1

The correct option is B $(-4,1)$

The equation of parabola is
$x^2+8x+12y+4=0\Rightarrow (x+4{)}^2-16+12y+4=0\Rightarrow (x+4{)}^2-12+12y=0\Rightarrow (x+4{)}^2=-12y+12\Rightarrow (x+4{)}^2=-12(y-1)$
$\therefore$ Vertex is $(-4,1)$