Question

The vertex of the parabola (y − 2)² = 16 (x − 1) is
(a) (1, 2)
(b) (−1, 2)
(c) (1, −2)
(d) (2, 1)

Answer 1

(a) (1, 2)

Given:
(y − 2)² = 16 (x − 1)

Let $X=x-1,Y=y-2$

∴ $Y^2=16X$

Vertex = $\left(X=0,Y=0\right)=\left(x-1=0,y-2=0\right)=\left(x=1,y=2\right)$

Hence, the vertex is at (1, 2).