The vertex of the quadratic curve y=ax2+bx+c lies in the fourth quadrant, if
A
ax2+bx+c<0∀XεR and b>0
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B
ax2+bx+c<0∀XεR and b<0
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C
ax2+bx+c<0 for some x,a>0 and b>0
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D
ax2+bx+c<0 for some x,a<0 and b<0
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Solution
The correct option is Aax2+bx+c<0∀XεR and b>0 For x taking real values, vertex of the parabola lies in fourth quadrant if a<0, i.e, parobola should be downward parabola