Question

The vertex of translated parabola formed by translating $x^2=16y$ by $3$ units along positive x-axis and $1$ unit along positive y-axis is

Answer 1

Given the parabola $x^2=16y$ which is translated 3 units along positive x-axis and 1 unit along positive y-axis.
So, the equation of translated parabola will be
$\Rightarrow (x-3{)}^2=16(y-1)$
Hence, the vertex of this translated parabola is $(3,1).$