Question

The vertical and horizontal components of Earth's magnetic field are $2\times {10}^{-8}T$ and $3.46\times {10}^{-5}T$ respectively. Calculate the dip at that place.

Answer 1

$B_V=3.46\times {10}^{-5}T{B}_H=2\times {10}^{-8}T$
Dip, $I=ta{n}^{-1}\left(\frac{B_V}{B_H}\right)=ta{n}^{-1}\left(\frac{3.46\times {10}^{-5}}{2\times {10}^{-8}}\right)={89.96}^{\circ }$