The vertical angle of an isoceles triangle is three time the sum of its base angles. Find all the angles of the triangle.
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Solution
In ΔABC AB = AC ∠A=3(∠B+∠C) Let ∠B=x ∴∠C=x ∴∠B+∠C=2x,Hence∠A=3x Thus by angle sum property 2x+3x=180 5x=180 x=1805 Thus, ∠C=∠B=1805 = 36∘ Angle A = 108∘