the vertical angle of an isosceles triangle measures ${(5 t - 18)}^{0}$ and one of the base angles measure $3 t^{0}$ the value of t is

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Solution

The correct option is C 18
$∠ A = (5 t - 18)^{o}$
$∠ B = ∠ C = 3 t^{o}$
By Angle sum property:-
$5 t - 18 - 3 t + 3 t = 180^{o}$
$\Rightarrow 11 t = 198$
$\Rightarrow t = \frac{198}{11} = 18^{o}$ .

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