Question

The vertical component of earth's magnetic field at a place is $\sqrt{3}$ times the horizontal component the value of angle of dip at this place is

• A. ${30}^0$
• B. ${45}^0$
• C. ${60}^0$
• D. ${90}^0$

Answer 1

The correct option is C ${60}^0$

As, $B_V=\sqrt{3}{B}_H$
Also, $tan\delta =\frac{B_V}{B_H}=\frac{\sqrt{3}{B}_H}{B_H}=\sqrt{3}or\delta =ta{n}^{-1}\left(\sqrt{3}\right)={60}^0$
$\therefore$ Angle of dip, $\delta$$={60}^0$.