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Byju's Answer

Standard XII

Physics

Equations of Motion

The vertical ...

Question

The vertical component of velocity of a projectile at its maximum height (u = velocity of projection, $θ =$ angle of projection) is :

u sin θ

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u cos θ

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\frac{u}{sin θ}

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Zero

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\frac{u}{cos θ}

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Solution

The correct option is D Zero
The vertical component of velocity of a projectile at maximum height is zero because at maximum height it has only horizontal component of velocity.

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Similar questions

Q. Explain how

u cos θ

is the horizontal component and

u sin θ

the vertical component when a projectile is projected at an angle

θ

from the horizontal.

Q. A projectile is thrown with a speed

u

at an angle

θ

with the vertical. Its average velocity between the instants, it crosses half the maximum height is :

Q. A stone projected with a velocity with a velocity

u

at an angle

θ

with the horizontal reaches maximum height

H_{1}

. When it is projected with the velocity

u

at an angle

(\frac{π}{2} - θ)

with the horizontal, it reaches maximum height

H_{2}

. The relation between the horizontal range

R

of the projectile, heights

H_{1}

and

H_{2}

Q. A stone projected with a velocity

u

at an angle

θ

with the horizontal reaches maximum height

H_{1}

. When it is projected with velocity

u

at an angle

(\frac{π}{2} - θ)

with the horizontal, it reaches maximum height

H_{2}

. The relation between the horizontal range

R

of the projectile,

H_{1}

and

H_{2}

Q. Find the average velocity of a projectile between the instants it crosses one third of the maximum height. It is projected with

u

making an angle

θ

with the vertical.

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The vertical component of velocity of a projectile at its maximum height (u = velocity of projection, θ= angle of projection) is :

The correct option is D ZeroThe vertical component of velocity of a projectile at maximum height is zero because at maximum height it has only horizontal component of velocity.

The vertical component of velocity of a projectile at its maximum height (u = velocity of projection, $θ =$ angle of projection) is :

The correct option is D Zero
The vertical component of velocity of a projectile at maximum height is zero because at maximum height it has only horizontal component of velocity.