Question

The vertical extension in a light spring by a weight of 1 kg suspended from the wire is 9.8 cm. The period of oscillation.

• A. 20π sec
• B. 2π sec
• C. 2π/10 sec
• D. 200π sec

Answer 1

The correct option is C

2π/10 sec

$\because mg=kx\Rightarrow \frac{m}{k}=\frac{x}{g}\Rightarrow T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{x}{g}}$

= $2\pi \sqrt{\frac{9.8\times {10}^{-2}}{9.8}}=\frac{2\pi }{10}$ sec