Question

The vertical height of a conical tent is $42$ dm and its diameter of the base is $54$ dm. How many persons can it accommodate, if each person is to be allowed $2916$ ${\text{dm}}^3$ of space ? $(\pi =22/7)$

Answer 1

Volume of the cone i.e capacity of the cone
$=\frac{1}{3}\pi r^{2}h$
$=\frac{1}{3}\times \frac{22}{7}\times 27\times 27\times 42d{m}^3$
$=32076d{m}^3$
$\therefore$ No.of person$=\frac{32076}{2916}=11$