The vertices of a ΔOBC are O(0, 0), B(–3, –1) and C(–1, –3). The equation of a line parallel to BC and intersecting sides OB and OC whose distance from the origin is 12, is
A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A The equation of line BC is x + y + 4 = 0 ∴ Equation of a line parallel to BC is x + y + k = 0 This is at a distance 12 from the origin
∴∣∣∣k√2∣∣∣=12∴k=±1√2 Since BC and the required line are on the same side of the origin ∴k=1√2,theequationisx+y+1√2=0