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Question

The vertices of a ΔOBC are O(0, 0), B(–3, –1) and C(–1, –3). The equation of a line parallel to BC and intersecting sides OB and OC whose distance from the origin is 12, is

A
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B
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C
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D
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Solution

The correct option is A
The equation of line BC is x + y + 4 = 0
Equation of a line parallel to BC is x + y + k = 0
This is at a distance 12 from the origin

k2=12 k=±12
Since BC and the required line are on the same side of the origin
k=12,the equation is x+y+12=0

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