The vertices of a hyperbola are (2, 0), (–2, 0) and the foci are (3, 0), (–3, 0). The equation of the hyperbola is
x25−y24=1
x24−y25=1
x25−y22=1
x22−y25=1
Centre=(0,0),a=2,ae=3⇒e=32
b2=a2(e2−1)=a2 e2−a2=9−4=5
equation of the hyperbola is x24−y25=1
Find the equation of the hyperbola whose vertices are (0, ±3) and the foci are (0, ±5).
Find the equation of the hyperbola with foci (0, ± 3) and vertices (0,±√112).
If (0,±4) and (0,±2) be the foci and vertices of a hyperbola, then its equation is