wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The vertices of a hyperbola are (2, 0), (–2, 0) and the foci are (3, 0), (–3, 0). The equation of the hyperbola is


A

x25y24=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

x24y25=1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

x25y22=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x22y25=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

x24y25=1


Centre=(0,0),a=2,ae=3e=32

b2=a2(e21)=a2 e2a2=94=5

equation of the hyperbola is x24y25=1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon