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Question

The vertices of a ABC are A(1,2),B(4,5) and C(0,1). Find the slopes of the altitudes of the triangle.
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Solution

Let AD,BE and CF be the altitudes of a ABC. Slope of BC=150+4=1 Since the altitude AD is a perpendicular to BC, Slope of AD=1 m1m2=1 Slope of AC=1201=1 Thus, Slope of BE=1 BEAC Also, Slope of AB=5241=35 Slope of CF=53 CFAB

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