The vertices of a triangle AOD are (4,0) (0,0) (0,3) If the triangle is rotated clockwise about its circumcenter till AD returns to its original position then the vertices of the triangle in its new positions are
A
(3,0), (0,0), (0,4)
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B
(-3,0), (0,0), (0, -4)
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C
(3,4), (0,0), (0,4)
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D
(-4,0), (0,0), (0,0), (0,3)
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Solution
The correct option is A (3,0), (0,0), (0,4) From the diagram we can find the answer