Question

The vertices of a triangle are A $(2,2)$, B $(-4,-4)$, C $(5,-8)$. Then, if the length of the median through C is $\sqrt{m}$.Find $m$

Answer 1

Mid point of AB $=(\frac{2-4}{2},\frac{2-4}{2})$
$=(-1,-1)=D$
Now $CD=\sqrt{(5+1{)}^2+(-8+1{)}^2}$
$=\sqrt{36+49}\sqrt{85}units$