The vertices of a triangle are A(–2, 8), B(1, 2) and C(7, –1).

i) Find the equation of the median AD.

ii) Find the equation of the altitude BE.

(4,1/2), x-y+1=0

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(2,1/4), 2x-y+1=0

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(4,1/2), x-2y+1=0

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(1,4/2), x-y+1=0

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Solution

The correct option is A
(4,1/2), x-y+1=0

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Similar questions

The vertices of a triangle are A(10,4), B(-4,9), and (-2,-1). Find the equation of its altitude which passes through (10,4)

A (7, - 1), B (- 2, 8)

C (1, 2)

(1, 4)

y^{2} = 12 x

(1, 2, - 3)

(2, - 2, 1)

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