Question

The vertices of a triangle are $A(2,2),B(-4,4),C(5,-8)$. Then, find the length of the median through $C$.

• A. $\sqrt{157}$
• B. $\sqrt{15}$
  
• C. $\sqrt{57}$
• D. None of these

Answer 1

The correct option is A $\sqrt{157}$

'D' is mid point

$\therefore D=(\frac{2-4}{2},\frac{2+4}{2})$

$D=(-1,3)$

$\therefore CD=\sqrt{[5-(-1){]}^2+(-8-3{)}^2}$

$=\sqrt{6^2+{11}^2}=\sqrt{157}$