Question

The vertices of a triangle are A(3, $-$4), B(5, 7) and C($-$4, 5). Find the slope of each side of the triangle ABC.

Answer 1

Given: The points A(3, $-$4), B(5, 7) and C($-$4, 5) are the vertices of a triangle.

We know that slope of a line = $\frac{y_2-y_1}{x_2-x_1}=\frac{y_1-y_2}{x_1-x_2}$

Now, we have the following:

Slope of AB =$\frac{-4-7}{3-5}=\frac{11}{2}$

Slope of BC =$\frac{7-5}{5-(-4)}=\frac{2}{9}$

Slope of AC = $\frac{-4-5}{3-(-4)}=-\frac{9}{7}$