Question

The vertices of $\Delta ABC$ are (-2, 1), (5, 4) and (2, -3) respectively. Find the area of triangle.

Answer 1

A(-2, 1), B(5, 4) and C(2, -3) be the vertices of triangle
So $x_1=-2,y_1=1;x_2=5,y_2=4;x_3=2,y_3=-3$
Area of $\Delta ABC$
= $\frac{1}{2}\left|[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]\right|$
= $\frac{1}{2}\left|[(-2)(4+3)+\left(5\right)(-3-1)+2(1-4)]\right|$
= $\frac{1}{2}\left|[-14+(-20)+(-6)]\right|$
= $\frac{1}{2}|-40|$
= 20 Sq unit