The vertices of ∆XYZ are X (3, 2), Y (– 4, 5) and Z (5, 3). The equation of the median through the vertex Y is:
16x + 5y + 20 = 0
2x – 3y + 16 = 0
9x – 10y – 60 = 0
5x + 16y – 60 = 0
The vertices of a triangle are A(10,4), B(-4,9), and (-2,-1). Find the equation of its altitude which passes through (10,4)
A(-1, 8), B(4, -2) and C(-5, -3) are the vertices of a triangle, find the equation of the median through (-1, 8).
Find the equation of the lines through the point of intersection of the lines x-3y+1 = 0 and 2x+5y-9 = 0 and whose distance from the origin is √5.