The voltage applied to an X-ray bulb increases to 1.5 times the initial voltage. The short wavelength limit of continuous X-ray spectrum shifts by 25 pm. Then
A
Initial voltage applied is 160×103kV
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B
Initial voltage applied is 80×103kV
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C
Initial wavelength is 75pm
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D
Final wavelength is 150pm
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Solution
The correct option is D Initial wavelength is 75pm λ=hceV λ1=2hc3eV λ−25=2hc3eV so, λλ−25=32 2λ=3λ−75 λ=75pm