The voltage gain of the following amplifier is

10

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100

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1000

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9.9

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Solution

The correct option is D $100$
Voltage gain $= \frac{o u p u t v o l t a g e (V_{o})}{i n p u t v o l t a g e (V_{i})}$
From Ohm's law $V = i R$
$∴$ Voltage gain, $A_{v} = \frac{R}{R_{i}} = \frac{100 k Ω}{1 k Ω} = 100$

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The voltage gain of the following amplifier is

The correct option is D 100Voltage gain=ouputvoltage(Vo)inputvoltage(Vi)From Ohm's law V=iR∴ Voltage gain, Av=RRi=100kΩ1kΩ=100

The correct option is D $100$
Voltage gain $= \frac{o u p u t v o l t a g e (V_{o})}{i n p u t v o l t a g e (V_{i})}$
From Ohm's law $V = i R$
$∴$ Voltage gain, $A_{v} = \frac{R}{R_{i}} = \frac{100 k Ω}{1 k Ω} = 100$