Question

The voltage of a battery is 10 V. Find the amount of work done to transfer a charge of 20 C from one terminal to the other.

Answer 1

Concept used: Electric field

Prerequisite: Knowledge of work done in an electric field

Given data:

1. The voltage of battery is V=10 V.
2. The charge given is Q=20 C.

The formula for the work done is given by,

$W=VQ$

Here, W is the work done.

Substitute the given values in the above equation,

$$\begin{gathered} W=\left(10\mathrm{V}\right)\left(20C\right) \\ W=200\mathrm{V}·\mathrm{C} \\ W=200\mathrm{J} \end{gathered}$$

Thus, the work done to move 20 C of charge is 200 J.