The voltage of a cell whose halfcells are given below is- Mg2-2e- Mgs-E0-2-37V Cu2-2e- Cus-E0-0-34V standard EMF of the cell is-

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EMF

The voltage o...

Question

The voltage of a cell whose halfcells are given below is:
$M g^{2 +} + 2 e^{-} \to M g (s); E^{0} = - 2.37 V$
$C u^{2 +} + 2 e^{-} \to C u (s); E^{0} = + 0.34 V$ standard EMF of the cell is:

1.03V

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1.36V

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2.7 V

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2.03V

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Solution

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M g^{2 +} + 2 e^{-} \to M g (s)

E = - 2.37 V

C u^{2 +} + 2 e^{-} \to C u (s)

E = + 0.34 V

M g^{2 +} + 2 e^{-} \to M g; E^{0} = - 2.37 V

Z n^{2 +} + 2 e^{-} \to Z n; E^{0} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.44 V

$C u - 2 e^{-} \to C u^{2 +}, E^{0} = - 0.347 V$

$S n - 2 e^{-} \to S n^{2 +}, E^{0} = + 0.143 V$

The EMF of the cell constructed with these electrodes is :

(E_{c e l l}^{0})

M g^{2 +} + 2 e^{-} \to M g (s); E^{0} = - 2.37 V

A g^{+} (a q) + e^{-} \to A g (s); E^{0} = + 0.80 V

Z n \to Z n^{+ +} + 2 e^{-}, E^{0} = 0.76 V

C u \to C u^{+ +} + 2 e^{-}, E^{0} = 0.34 V

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