Question

The voltage of an ac source varies with time according to the equation V = 200sin$\left(100\pi t\right).cos\left(100\pi t\right)$ where t is in seconds and V is in volts. Then

• A. The peak voltage of the source is 100 volts
• B. The peak voltage of the source is 50 volts
• C. The peak voltage of the source is $\frac{100}{\sqrt{2}}$ volts
• D. The frequency of the source is 50 Hz

Answer 1

The correct option is A The peak voltage of the source is 100 volts

$V=100\times 2sin100\pi tcos100\pi t=100sin200\pi t$
$\Rightarrow V_0=100$ Volts and Frequency =100Hz