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Question

The Voltage of an electromagnetic wave propagating in a coaxial cable with uniform characteristic impedance is V(l) = eγl+jωt Volts, where l is the distance along the length of the cable is meters, γ=(0.1+j40)m1 is the complex propagation constant, and ω=2π×109 rad/s is the angular frequency. The absolute value of the attenuation in the cable in dB/meter is
  1. 0.868

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Solution

The correct option is A 0.868
V(l)=V0eαlejβlejωt

Attenuation = |Input||Output|=|V0(0)||V0(l)|

Attenuation per meter = |V0||V0(1m)|=eα

Attenuation in dB/m = (20logeα)dB/m

= 20(0.1)loge = 0.868 dB/m

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