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Characteristics of Equilibrium Constant

The volume an...

Question

The volume and no of molecules of $C O_{2}$ liberated at STP if $50 g$ of $C a C O_{3}$ is treated with dilute hydrochloric acid which contains $7.3 g$ of dissolved $H C l$ gas.

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Solution

$C a C O_{3} + 2 H C l ⟶ C a C l_{2} + H_{2} O + C O_{2}$
1 mole + 2 mole $⟶$ 1 mole + 1mole + 1 mole
no. of moles of $C a C O_{3}$ = $\frac{g i v e n m a s s}{m o l a r m a s s} = \frac{50}{100} = 0.5 m o l e$
HCl is limiting reagent.
0.5 mole of $C a C O_{3}$ gives = 0.5 mole of $C O_{2}$
1 mole of $C O_{2}$ = $6.022 \times 10^{23}$
0.5 mole of $C O_{2}$ = $0.5 \times 6.022 \times 10^{23} = 3.011 \times 10^{23}$ molecules.
1 mole of $C O_{2} a t S . T . P c o n t a i n s v o l u m e o f 22.4 L$
0.5 mole of $C O_{2} a t S . T . P c o n t a i n s v o l u m e o f 11.2 L$

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