The volume generated by rotating the triangle with vertices at (0,0),(3,0) and (3,3) about axis is:
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Solution
The given points form a isosceles right angled triangle with base of 3 units along x-axis and height of 3 units perpendicular to x axis. If we rotate the triangle about its base BO, then we will get a cone centred at B, with base radius r=BO=3 units and height h=AB=3 units Therefore the volume of the cone thus formed will be V=πr2h3 =π(BO2×AB3) =π(32×33) =9π.