Question

The volume in litre of $C{O}_2$ liberated at STP When 10 g of 90% pure limestone is heated completely, is:

• A. 22.4 L
• B. 2.24 L
• C. 20.16 L
• D. 2.016 L

Answer 1

Answer: (D)

2.016 L

$\underset{\left(100g\right)}{\underset{1mole}{CaC{O}_3}}\to CaO+\underset{22.4litreatSTP}{C{O}_2\left(g\right)}$

$\because$ 100 g $CaC{O}_3=22.4LC{O}_3$ at STP

$\therefore$ 9 g $CaC{o}_3=\frac{22.4}{100}\times 9LC{O}_2$ at STP

$=2.016LC{O}_2$ at STP