Question

The volume (in litres) of $C{O}_2$ obtained at STP by the complete decomposition of $9.85$ g of $BaC{O}_3$ is :

(Given that the atomic weight of $Ba$ is $137$ amu.)

• A. $2.24$
• B. $1.61$
• C. $0.84$
• D. $0.56$

Answer 1

Answer: (B)

$1.61$

$BaC{O}_3\to BaO+C{O}_2$

$\frac{9.85}{137}$ $\frac{9.85}{137}$

$V_{C{O}_2}=\frac{9.85}{197}\times 22.4=1.61lit$